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Say you have an array for which the ith element is the price of a given stock on day i.

Design an algorithm to find the maximum profit. You may complete as many transactions as you like (i.e., buy one and sell one share of the stock multiple times).

Note: You may not engage in multiple transactions at the same time (i.e., you must sell the stock before you buy again).

Example 1:

Input: [7,1,5,3,6,4]

Output: 7

Explanation: Buy on day 2 (price = 1) and sell on day 3 (price = 5), profit = 5-1 = 4.

Then buy on day 4 (price = 3) and sell on day 5 (price = 6), profit = 6-3 = 3.
Example 2:

Input: [1,2,3,4,5]

Output: 4

Explanation: Buy on day 1 (price = 1) and sell on day 5 (price = 5), profit = 5-1 = 4.

Note that you cannot buy on day 1, buy on day 2 and sell them later, as you are

engaging multiple transactions at the same time. You must sell before buying again.

Example 3:

Input: [7,6,4,3,1]

Output: 0

Explanation: In this case, no transaction is done, i.e. max profit = 0.

```
class Solution {
public int maxProfit(int[] prices) {
int[] dp = new int[2];
dp[1] = Integer.MIN_VALUE;
for (int price : prices) {
dp[0] = Math.max(dp[0], dp[1] + price);
dp[1] = Math.max(dp[1], dp[0] - price);
}
return dp[0];
}
/*
执行用时 :2 ms, 在所有 Java 提交中击败了26.28%的用户
内存消耗 :42.5 MB, 在所有 Java 提交中击败了5.04%的用户
*/
}
```

Reference

https://leetcode-cn.com/problems/best-time-to-buy-and-sell-stock-ii/submissions